In a titration of 0.35 M HCl and 0.35 M NaOH, how much NaOH should be added to 45.0 ml of HCl to completely neutralize the acid?

• Dotz: It would be the same amount. So, 45 ml of NaOH is required to be added to the 45 ml of HCI to neutralize the acid fully. Here is a brief calculation:
  
  Firstly, here is your formula: M(HCI) x V(HCI) = M(NaOh) x V(NaOH) 
  With the values put in: 0.35 x 45 = 0.35 x V(NaOH) 
  = 45 ml. 
  There is 45 ml of V(NaOH)
  
  Let me know if you need anything else. :)
  
             - Dotz