CDs and DVDs Solve by setting up a system of linear equations with 2 variables and 2 unknowns. CDs cost $5.96 more than DVDs at All Bets Are Off Electronics. How much would 6 CDs and 2 DVDs cost if 5 CDs and 2 DVDs cost $127.73?

• MsEHolt: 6 CDs and 2 DVDs would cost $147.68.
  
  Let c be the cost of a CD and d be the cost of a DVD.
  
  We know that c = d+5.96.
  
  We also know that 5c+2d = 127.73.
  
  Substituting our value of c from the first equation into the second one, we have
  5(d+5.96)+2d = 127.73
  
  Using the distributive property,
  5*d+5*5.96+2d = 127.73
  5d+29.80+2d = 127.73
  
  Combining like terms,
  7d+29.80 = 127.73
  
  Subtract 29.80 from both sides:
  7d+29.80-29.80=127.73-29.80
  7d = 97.93
  
  Divide both sides by 7:
  7d/7 = 97.93/7
  d = 13.99
  c = d + 5.96 = 13.99+5.96 = 19.95
  
  6 CDs and 2 DVDs would be
  6(19.95)+2(13.99) = 147.68
• MrRoyal:

  The relationship between the total cost and the costs of CDs and DVDs are represented by a linear function.

  The cost of 6 CDs and 2 DVDs is $147.68

  Let:

  [tex]C \to CDs[/tex]

  [tex]D \to DVDs[/tex]

  From the question, we have:

  [tex]C = D + 5.96[/tex]

  [tex]5C + 2D = 127.73[/tex]

  Substitute [tex]C = D + 5.96[/tex] in [tex]5C + 2D = 127.73[/tex]

  [tex]5 \times (D + 5.96) + 2D = 127.73[/tex]

  [tex]5D + 29.8 + 2D = 127.73[/tex]

  Collect like terms

  [tex]5D + 2D = 127.73 - 29.8[/tex]

  [tex]7D = 97.93[/tex]

  Divide both sides by 7

  [tex]D = 13.99[/tex]

  Substitute [tex]D = 13.99[/tex] in [tex]C = D + 5.96[/tex]

  [tex]C = 13.99 + 5.96[/tex]

  [tex]C = 19.95[/tex]

  The cost of 6 CDs & 2 DVDs is represented as:

  [tex]Cost =6C + 2D[/tex]

  So, we have:

  [tex]Cost =6 \times 19.95 + 2 \times 13.99[/tex]

  [tex]Cost =147.68[/tex]

  Hence, the cost of 6 CDs & 2 DVDs is $147.68

  Read more about linear equations at:

  https://brainly.com/question/11897796