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Answer: ∠EFG=∠QFG
Step-by-step explanation:
In the given picture we have two triangles ΔFEG and ΔFQG  in which EF=FQ
and GF=GF [ by reflexive property].
To apply SAS postulate we need included angle of sides EF, GF and FQ, GF.
Therefore, the additional information can be used to prove ΔFEG ≅ ΔFQG is given by :-
∠EFG=∠QFG
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