Complete the equation of the line through (-6,5) and (-3,-3) Use exact numbers. y=

• choixongdong: (-6,5) and (-3,-3) 
  slope = (5+3)/(-6 + 3) = 8/-3 = -8/3
  
  y = mx + b
  b = y - mx
  b = -3 - (-8/3)(-3)
  b = -3 - 8
  b = -11
  
  equation
  y = -8/3 x - 11
  
  hope it helps
• jainveenamrata:

  The equation of the line passing through the points (-6,5) and (-3,-3) will be y = -(8/3)x - 11.

  What is the equation of a line passing through two points?

  Let the equation of the line pass through (x₁, y₁) and (x₂, y₂).

  Then the equation of the line is given as,

  [tex]\rm (y - y_2) = \left (\dfrac{y_2 - y_1}{x_2 - x_1} \right ) (x - x_2)[/tex]

  The points are given below.

  (-6,5) and (-3,-3)

  Then the equation of the line passing through the points (-6,5) and (-3,-3) will be

  [tex]\rm (y + 3) = \left (\dfrac{-3-5}{-3+6} \right ) (x + 3)[/tex]

  Simplify the equation, then the equation of the line will be

  y + 3 = -(8/3)(x + 3)

  y = -(8/3)x - 8 - 3

  y = -(8/3)x - 11

  Then the equation of the line passing through the points (-6,5) and (-3,-3) will be y = -(8/3)x - 11.

  More about the line passing through two points link is given below.

  https://brainly.com/question/12740817

  #SPJ2