HELP ME PLEASE!!!!!! The body of a 154-pound person contains approximately 2 X 10^-1 milligrams of gold and 6 X 10^1 milligrams of aluminum. Based on this information, the number of milligrams of aluminum in the body is how many times the number of milligrams of gold in the body?

• Cetacea:

  The number of milligrams of aluminium in the body is 300 times the number of milligrams of gold in the body.

  Given amount of gold is = g =  [tex]2 * 10^{-1}[/tex] mg.

  Given amount of aluminium is = a = [tex]6*10^1[/tex] mg.

  Let the number of milligrams of aluminium in the body is "k" times the number of milligrams of gold in the body.

  So, a = kg

  [tex]k=\frac{a}{g}\\k=\frac{6\cdot10^{1}}{2\cdot10^{-1}}\\k=300[/tex]

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